Base | Representation |
---|---|
bin | 10011100010111110010… |
… | …101001001100001001011 |
3 | 11202102002112001221012100 |
4 | 103202332111021201023 |
5 | 134001410042331103 |
6 | 2505022414444443 |
7 | 166021214133030 |
oct | 23427625114113 |
9 | 4672075057170 |
10 | 1343223011403 |
11 | 478726410419 |
12 | 1983aa803723 |
13 | 99885b14530 |
14 | 49025c11387 |
15 | 24e188535a3 |
hex | 138be54984b |
1343223011403 has 48 divisors (see below), whose sum is σ = 2388081346560. Its totient is φ = 708474866112.
The previous prime is 1343223011399. The next prime is 1343223011447. The reversal of 1343223011403 is 3041103223431.
It is a happy number.
1343223011403 is a `hidden beast` number, since 1 + 34 + 3 + 223 + 0 + 1 + 1 + 403 = 666.
It is not a de Polignac number, because 1343223011403 - 22 = 1343223011399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1343223011003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21412558 + ... + 21475196.
It is an arithmetic number, because the mean of its divisors is an integer number (49751694720).
Almost surely, 21343223011403 is an apocalyptic number.
1343223011403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1343223011403 is a deficient number, since it is larger than the sum of its proper divisors (1044858335157).
1343223011403 is a wasteful number, since it uses less digits than its factorization.
1343223011403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88848 (or 88845 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 1343223011403 its reverse (3041103223431), we get a palindrome (4384326234834).
The spelling of 1343223011403 in words is "one trillion, three hundred forty-three billion, two hundred twenty-three million, eleven thousand, four hundred three".
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