Base | Representation |
---|---|
bin | 111110100011000111… |
… | …1011011000001101001 |
3 | 110211201011100122120122 |
4 | 1331012033123001221 |
5 | 4200043020343103 |
6 | 141412403533025 |
7 | 12463430565125 |
oct | 1750617330151 |
9 | 424634318518 |
10 | 134322434153 |
11 | 51a6956a966 |
12 | 2204838a175 |
13 | c88854a38b |
14 | 6703592585 |
15 | 3762579b38 |
hex | 1f463db069 |
134322434153 has 2 divisors, whose sum is σ = 134322434154. Its totient is φ = 134322434152.
The previous prime is 134322434131. The next prime is 134322434179. The reversal of 134322434153 is 351434223431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99608409664 + 34714024489 = 315608^2 + 186317^2 .
It is a cyclic number.
It is not a de Polignac number, because 134322434153 - 220 = 134321385577 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (134322433153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67161217076 + 67161217077.
It is an arithmetic number, because the mean of its divisors is an integer number (67161217077).
Almost surely, 2134322434153 is an apocalyptic number.
It is an amenable number.
134322434153 is a deficient number, since it is larger than the sum of its proper divisors (1).
134322434153 is an equidigital number, since it uses as much as digits as its factorization.
134322434153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 35.
Adding to 134322434153 its reverse (351434223431), we get a palindrome (485756657584).
The spelling of 134322434153 in words is "one hundred thirty-four billion, three hundred twenty-two million, four hundred thirty-four thousand, one hundred fifty-three".
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