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13432440034103 = 41932058329437
BaseRepresentation
bin1100001101110111101111…
…0100010001001100110111
31202120010110211201101011212
43003131323310101030313
53230034114122042403
644322435555152035
72554314246264326
oct303357364211467
952503424641155
1013432440034103
114309736241932
12160b368ba561b
1376589b0536bc
143461c27140bd
1518461dedc4d8
hexc377bd11337

13432440034103 has 4 divisors (see below), whose sum is σ = 13464498363960. Its totient is φ = 13400381704248.

The previous prime is 13432440034063. The next prime is 13432440034129. The reversal of 13432440034103 is 30143004423431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13432440034103 - 214 = 13432440017719 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13432440034103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13432440034163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16029164300 + ... + 16029165137.

It is an arithmetic number, because the mean of its divisors is an integer number (3366124590990).

Almost surely, 213432440034103 is an apocalyptic number.

13432440034103 is a deficient number, since it is larger than the sum of its proper divisors (32058329857).

13432440034103 is an equidigital number, since it uses as much as digits as its factorization.

13432440034103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32058329856.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 13432440034103 its reverse (30143004423431), we get a palindrome (43575444457534).

The spelling of 13432440034103 in words is "thirteen trillion, four hundred thirty-two billion, four hundred forty million, thirty-four thousand, one hundred three".

Divisors: 1 419 32058329437 13432440034103