Base | Representation |
---|---|
bin | 111110100011001101… |
… | …0101111111001010001 |
3 | 110211201100221111100222 |
4 | 1331012122233321101 |
5 | 4200044300400332 |
6 | 141412551322425 |
7 | 12463465042235 |
oct | 1750632577121 |
9 | 424640844328 |
10 | 134325403217 |
11 | 51a70208635 |
12 | 22049380415 |
13 | c889049915 |
14 | 6703b265c5 |
15 | 3762964712 |
hex | 1f466afe51 |
134325403217 has 2 divisors, whose sum is σ = 134325403218. Its totient is φ = 134325403216.
The previous prime is 134325403193. The next prime is 134325403249. The reversal of 134325403217 is 712304523431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73942661776 + 60382741441 = 271924^2 + 245729^2 .
It is a cyclic number.
It is not a de Polignac number, because 134325403217 - 220 = 134324354641 is a prime.
It is not a weakly prime, because it can be changed into another prime (134325409217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67162701608 + 67162701609.
It is an arithmetic number, because the mean of its divisors is an integer number (67162701609).
Almost surely, 2134325403217 is an apocalyptic number.
It is an amenable number.
134325403217 is a deficient number, since it is larger than the sum of its proper divisors (1).
134325403217 is an equidigital number, since it uses as much as digits as its factorization.
134325403217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 134325403217 its reverse (712304523431), we get a palindrome (846629926648).
The spelling of 134325403217 in words is "one hundred thirty-four billion, three hundred twenty-five million, four hundred three thousand, two hundred seventeen".
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