134325403237 has 4 divisors (see below), whose sum is σ = 134723995276. Its totient is φ = 133926811200.

The previous prime is 134325403217. The next prime is 134325403249. The reversal of 134325403237 is 732304523431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 732304523431 = 13 ⋅56331117187.

It can be written as a sum of positive squares in 2 ways, for example, as 63355910436 + 70969492801 = 251706^2 + 266401^2 .

It is a cyclic number.

It is not a de Polignac number, because 134325403237 - 2¹⁵ = 134325370469 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134325403196 and 134325403205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134325403217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199295514 + ... + 199296187.

It is an arithmetic number, because the mean of its divisors is an integer number (33680998819).

Almost surely, 2^134325403237 is an apocalyptic number.

It is an amenable number.

134325403237 is a deficient number, since it is larger than the sum of its proper divisors (398592039).

134325403237 is an equidigital number, since it uses as much as digits as its factorization.

134325403237 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 398592038.

The product of its (nonzero) digits is 181440, while the sum is 37.

Adding to 134325403237 its reverse (732304523431), we get a palindrome (866629926668).

The spelling of 134325403237 in words is "one hundred thirty-four billion, three hundred twenty-five million, four hundred three thousand, two hundred thirty-seven".