Base | Representation |
---|---|
bin | 111110100011011000… |
… | …0010001000011000001 |
3 | 110211201202120002010002 |
4 | 1331012300101003001 |
5 | 4200102221402113 |
6 | 141413312245345 |
7 | 12463564014614 |
oct | 1750660210301 |
9 | 424652502102 |
10 | 134331044033 |
11 | 51a7341066a |
12 | 2204b240855 |
13 | c88a273294 |
14 | 670479417b |
15 | 37631cac58 |
hex | 1f46c110c1 |
134331044033 has 2 divisors, whose sum is σ = 134331044034. Its totient is φ = 134331044032.
The previous prime is 134331043969. The next prime is 134331044041. The reversal of 134331044033 is 330440133431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109307600689 + 25023443344 = 330617^2 + 158188^2 .
It is a cyclic number.
It is not a de Polignac number, because 134331044033 - 26 = 134331043969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134331043987 and 134331044005.
It is not a weakly prime, because it can be changed into another prime (134331044233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165522016 + 67165522017.
It is an arithmetic number, because the mean of its divisors is an integer number (67165522017).
Almost surely, 2134331044033 is an apocalyptic number.
It is an amenable number.
134331044033 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331044033 is an equidigital number, since it uses as much as digits as its factorization.
134331044033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 134331044033 its reverse (330440133431), we get a palindrome (464771177464).
The spelling of 134331044033 in words is "one hundred thirty-four billion, three hundred thirty-one million, forty-four thousand, thirty-three".
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