1343311303 has 4 divisors (see below), whose sum is σ = 1346856040. Its totient is φ = 1339766568.

The previous prime is 1343311273. The next prime is 1343311309. The reversal of 1343311303 is 3031133431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3031133431 = 89 ⋅34057679.

It is a cyclic number.

It is not a de Polignac number, because 1343311303 - 2²¹ = 1341214151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343311309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1771800 + ... + 1772557.

It is an arithmetic number, because the mean of its divisors is an integer number (336714010).

Almost surely, 2^1343311303 is an apocalyptic number.

1343311303 is a deficient number, since it is larger than the sum of its proper divisors (3544737).

1343311303 is an equidigital number, since it uses as much as digits as its factorization.

1343311303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3544736.

The product of its (nonzero) digits is 972, while the sum is 22.

The square root of 1343311303 is about 36651.2114806591. The cubic root of 1343311303 is about 1103.3811400523.

Adding to 1343311303 its reverse (3031133431), we get a palindrome (4374444734).

The spelling of 1343311303 in words is "one billion, three hundred forty-three million, three hundred eleven thousand, three hundred three".