1343313530341 has 4 divisors (see below), whose sum is σ = 1355201260812. Its totient is φ = 1331425799872.

The previous prime is 1343313530333. The next prime is 1343313530407. The reversal of 1343313530341 is 1430353133431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 416818728225 + 926494802116 = 645615^2 + 962546^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343313530341 - 2³ = 1343313530333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343313530297 and 1343313530306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343313530311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5943865066 + ... + 5943865291.

It is an arithmetic number, because the mean of its divisors is an integer number (338800315203).

Almost surely, 2^{1343313530341} is an apocalyptic number.

It is an amenable number.

1343313530341 is a deficient number, since it is larger than the sum of its proper divisors (11887730471).

1343313530341 is a wasteful number, since it uses less digits than its factorization.

1343313530341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11887730470.

The product of its (nonzero) digits is 58320, while the sum is 34.

Adding to 1343313530341 its reverse (1430353133431), we get a palindrome (2773666663772).

The spelling of 1343313530341 in words is "one trillion, three hundred forty-three billion, three hundred thirteen million, five hundred thirty thousand, three hundred forty-one".