Base | Representation |
---|---|
bin | 11110100010110001111000… |
… | …111000000001010110100011 |
3 | 122121121221212222111120011211 |
4 | 132202301320320001112203 |
5 | 120101341224311214334 |
6 | 1153411001010050551 |
7 | 40203060640455163 |
oct | 3642617070012643 |
9 | 577557788446154 |
10 | 134331425101219 |
11 | 39890701502825 |
12 | 130963b6579a57 |
13 | 59c55258a1368 |
14 | 25259660525a3 |
15 | 107e4069dda64 |
hex | 7a2c78e015a3 |
134331425101219 has 2 divisors, whose sum is σ = 134331425101220. Its totient is φ = 134331425101218.
The previous prime is 134331425101201. The next prime is 134331425101243. The reversal of 134331425101219 is 912101524133431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134331425101219 - 25 = 134331425101187 is a prime.
It is a super-2 number, since 2×1343314251012192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134331425101019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165712550609 + 67165712550610.
It is an arithmetic number, because the mean of its divisors is an integer number (67165712550610).
Almost surely, 2134331425101219 is an apocalyptic number.
134331425101219 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331425101219 is an equidigital number, since it uses as much as digits as its factorization.
134331425101219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 134331425101219 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, four hundred twenty-five million, one hundred one thousand, two hundred nineteen".
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