Base | Representation |
---|---|
bin | 10011100011000011110… |
… | …001100000001000001001 |
3 | 11202102022212220101221002 |
4 | 103203003301200020021 |
5 | 134002101432030441 |
6 | 2505035440024345 |
7 | 166023403260251 |
oct | 23430361401011 |
9 | 4672285811832 |
10 | 1343314330121 |
11 | 478772a12535 |
12 | 1984153020b5 |
13 | 9989ba0878a |
14 | 49033dc2961 |
15 | 24e21890b9b |
hex | 138c3c60209 |
1343314330121 has 2 divisors, whose sum is σ = 1343314330122. Its totient is φ = 1343314330120.
The previous prime is 1343314330117. The next prime is 1343314330181. The reversal of 1343314330121 is 1210334133431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1071247770121 + 272066560000 = 1035011^2 + 521600^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343314330121 - 22 = 1343314330117 is a prime.
It is not a weakly prime, because it can be changed into another prime (1343314330181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657165060 + 671657165061.
It is an arithmetic number, because the mean of its divisors is an integer number (671657165061).
Almost surely, 21343314330121 is an apocalyptic number.
It is an amenable number.
1343314330121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343314330121 is an equidigital number, since it uses as much as digits as its factorization.
1343314330121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 1343314330121 its reverse (1210334133431), we get a palindrome (2553648463552).
The spelling of 1343314330121 in words is "one trillion, three hundred forty-three billion, three hundred fourteen million, three hundred thirty thousand, one hundred twenty-one".
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