Base | Representation |
---|---|
bin | 10011100011000100001… |
… | …000000000111000111001 |
3 | 11202102100022000020001222 |
4 | 103203010020000320321 |
5 | 134002104434401411 |
6 | 2505040210321425 |
7 | 166023504366344 |
oct | 23430410007071 |
9 | 4672308006058 |
10 | 1343320231481 |
11 | 478776283298 |
12 | 198417289275 |
13 | 9989ccc38c7 |
14 | 49034abb45b |
15 | 24e221594db |
hex | 138c4200e39 |
1343320231481 has 2 divisors, whose sum is σ = 1343320231482. Its totient is φ = 1343320231480.
The previous prime is 1343320231459. The next prime is 1343320231501. The reversal of 1343320231481 is 1841320233431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 859126925881 + 484193305600 = 926891^2 + 695840^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343320231481 - 222 = 1343316037177 is a prime.
It is a super-2 number, since 2×13433202314812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1343320231441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671660115740 + 671660115741.
It is an arithmetic number, because the mean of its divisors is an integer number (671660115741).
Almost surely, 21343320231481 is an apocalyptic number.
It is an amenable number.
1343320231481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343320231481 is an equidigital number, since it uses as much as digits as its factorization.
1343320231481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 1343320231481 in words is "one trillion, three hundred forty-three billion, three hundred twenty million, two hundred thirty-one thousand, four hundred eighty-one".
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