Base | Representation |
---|---|
bin | 10011100011000100010… |
… | …000011100001010010110 |
3 | 11202102100110011110001122 |
4 | 103203010100130022112 |
5 | 134002111021042332 |
6 | 2505040325523542 |
7 | 166023532226231 |
oct | 23430420341226 |
9 | 4672313143048 |
10 | 1343322440342 |
11 | 4787775518a3 |
12 | 198417b735b2 |
13 | 998a05b811c |
14 | 490350d4418 |
15 | 24e22443c12 |
hex | 138c441c296 |
1343322440342 has 4 divisors (see below), whose sum is σ = 2014983660516. Its totient is φ = 671661220170.
The previous prime is 1343322440333. The next prime is 1343322440351. The reversal of 1343322440342 is 2430442233431.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1343322440333) and next prime (1343322440351).
It is a super-2 number, since 2×13433224403422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335830610084 + ... + 335830610087.
It is an arithmetic number, because the mean of its divisors is an integer number (503745915129).
Almost surely, 21343322440342 is an apocalyptic number.
1343322440342 is a deficient number, since it is larger than the sum of its proper divisors (671661220174).
1343322440342 is an equidigital number, since it uses as much as digits as its factorization.
1343322440342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 671661220173.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 1343322440342 its reverse (2430442233431), we get a palindrome (3773764673773).
The spelling of 1343322440342 in words is "one trillion, three hundred forty-three billion, three hundred twenty-two million, four hundred forty thousand, three hundred forty-two".
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