Base | Representation |
---|---|
bin | 11110100010110010101101… |
… | …001101010110000000111001 |
3 | 122121122001011011121211110022 |
4 | 132202302231031112000321 |
5 | 120101400024043343410 |
6 | 1153411224052500225 |
7 | 40203121461415166 |
oct | 3642625515260071 |
9 | 577561134554408 |
10 | 134332303106105 |
11 | 398910120818a5 |
12 | 1309660061a675 |
13 | 59c5635766490 |
14 | 2525a0a8c506d |
15 | 107e458b23455 |
hex | 7a2cad356039 |
134332303106105 has 16 divisors (see below), whose sum is σ = 175284092605440. Its totient is φ = 98236139802048.
The previous prime is 134332303106069. The next prime is 134332303106153. The reversal of 134332303106105 is 501601303233431.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 134332303106105 - 238 = 134057425199161 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10032278825 + ... + 10032292214.
It is an arithmetic number, because the mean of its divisors is an integer number (10955255787840).
Almost surely, 2134332303106105 is an apocalyptic number.
It is an amenable number.
134332303106105 is a deficient number, since it is larger than the sum of its proper divisors (40951789499335).
134332303106105 is a wasteful number, since it uses less digits than its factorization.
134332303106105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20064571160.
The product of its (nonzero) digits is 58320, while the sum is 35.
Adding to 134332303106105 its reverse (501601303233431), we get a palindrome (635933606339536).
The spelling of 134332303106105 in words is "one hundred thirty-four trillion, three hundred thirty-two billion, three hundred three million, one hundred six thousand, one hundred five".
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