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134332303106153 is a prime number
BaseRepresentation
bin11110100010110010101101…
…001101010110000001101001
3122121122001011011121211112002
4132202302231031112001221
5120101400024043344103
61153411224052500345
740203121461415265
oct3642625515260151
9577561134554462
10134332303106153
1139891012081939
121309660061a6b5
1359c56357664c9
142525a0a8c50a5
15107e458b23488
hex7a2cad356069

134332303106153 has 2 divisors, whose sum is σ = 134332303106154. Its totient is φ = 134332303106152.

The previous prime is 134332303106069. The next prime is 134332303106167. The reversal of 134332303106153 is 351601303233431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131996822286169 + 2335480819984 = 11488987^2 + 1528228^2 .

It is a cyclic number.

It is not a de Polignac number, because 134332303106153 - 230 = 134331229364329 is a prime.

It is not a weakly prime, because it can be changed into another prime (134332303106653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166151553076 + 67166151553077.

It is an arithmetic number, because the mean of its divisors is an integer number (67166151553077).

Almost surely, 2134332303106153 is an apocalyptic number.

It is an amenable number.

134332303106153 is a deficient number, since it is larger than the sum of its proper divisors (1).

134332303106153 is an equidigital number, since it uses as much as digits as its factorization.

134332303106153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 174960, while the sum is 38.

Adding to 134332303106153 its reverse (351601303233431), we get a palindrome (485933606339584).

The spelling of 134332303106153 in words is "one hundred thirty-four trillion, three hundred thirty-two billion, three hundred three million, one hundred six thousand, one hundred fifty-three".