Base | Representation |
---|---|
bin | 11001000001010111… |
… | …01111111010011100 |
3 | 1021200012000100201111 |
4 | 30200223233322130 |
5 | 210002402204434 |
6 | 10100544551404 |
7 | 653613444433 |
oct | 144053577234 |
9 | 37605010644 |
10 | 13433241244 |
11 | 5773794a75 |
12 | 272a922564 |
13 | 1361081677 |
14 | 91610411a |
15 | 5394ce964 |
hex | 320aefe9c |
13433241244 has 12 divisors (see below), whose sum is σ = 23543741368. Its totient is φ = 6706458000.
The previous prime is 13433241229. The next prime is 13433241247. The reversal of 13433241244 is 44214233431.
It is a super-3 number, since 3×134332412443 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13433241247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2537682 + ... + 2542969.
Almost surely, 213433241244 is an apocalyptic number.
It is an amenable number.
13433241244 is a deficient number, since it is larger than the sum of its proper divisors (10110500124).
13433241244 is a wasteful number, since it uses less digits than its factorization.
13433241244 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5081316 (or 5081314 counting only the distinct ones).
The product of its digits is 27648, while the sum is 31.
Adding to 13433241244 its reverse (44214233431), we get a palindrome (57647474675).
The spelling of 13433241244 in words is "thirteen billion, four hundred thirty-three million, two hundred forty-one thousand, two hundred forty-four".
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