134333325040081 has 2 divisors, whose sum is σ = 134333325040082. Its totient is φ = 134333325040080.

The previous prime is 134333325040069. The next prime is 134333325040097. The reversal of 134333325040081 is 180040523333431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132375172604481 + 1958152435600 = 11505441^2 + 1399340^2 .

It is a cyclic number.

It is not a de Polignac number, because 134333325040081 - 2²⁵ = 134333291485649 is a prime.

It is a super-2 number, since 2×134333325040081² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134333325040781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166662520040 + 67166662520041.

It is an arithmetic number, because the mean of its divisors is an integer number (67166662520041).

Almost surely, 2^{134333325040081} is an apocalyptic number.

It is an amenable number.

134333325040081 is a deficient number, since it is larger than the sum of its proper divisors (1).

134333325040081 is an equidigital number, since it uses as much as digits as its factorization.

134333325040081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

The spelling of 134333325040081 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, three hundred twenty-five million, forty thousand, eighty-one".