Base | Representation |
---|---|
bin | 11001000001011000… |
… | …11111000011011101 |
3 | 1021200012101011120221 |
4 | 30200230133003131 |
5 | 210002424344313 |
6 | 10100553041341 |
7 | 653615210404 |
oct | 144054370335 |
9 | 37605334527 |
10 | 13433434333 |
11 | 5773907050 |
12 | 272a9b6251 |
13 | 136111b517 |
14 | 91615463b |
15 | 53951bc8d |
hex | 320b1f0dd |
13433434333 has 8 divisors (see below), whose sum is σ = 14656376736. Its totient is φ = 12210778800.
The previous prime is 13433434327. The next prime is 13433434337. The reversal of 13433434333 is 33343433431.
13433434333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13433434333 - 213 = 13433426141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13433434337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32835 + ... + 167167.
It is an arithmetic number, because the mean of its divisors is an integer number (1832047092).
Almost surely, 213433434333 is an apocalyptic number.
It is an amenable number.
13433434333 is a deficient number, since it is larger than the sum of its proper divisors (1222942403).
13433434333 is a wasteful number, since it uses less digits than its factorization.
13433434333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143435.
The product of its digits is 139968, while the sum is 34.
Adding to 13433434333 its reverse (33343433431), we get a palindrome (46776867764).
The spelling of 13433434333 in words is "thirteen billion, four hundred thirty-three million, four hundred thirty-four thousand, three hundred thirty-three".
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