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1343354117 = 7191907731
BaseRepresentation
bin101000000010001…
…1111010100000101
310110121202110102012
41100010133110011
510222344312432
6341144424005
745201215210
oct12004372405
93417673365
101343354117
1162a319916
12315a78005
131854073c1
14ca5a8777
157ce05cb2
hex5011f505

1343354117 has 4 divisors (see below), whose sum is σ = 1535261856. Its totient is φ = 1151446380.

The previous prime is 1343354101. The next prime is 1343354143. The reversal of 1343354117 is 7114533431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1343354117 - 24 = 1343354101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343354147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95953859 + ... + 95953872.

It is an arithmetic number, because the mean of its divisors is an integer number (383815464).

Almost surely, 21343354117 is an apocalyptic number.

It is an amenable number.

1343354117 is a deficient number, since it is larger than the sum of its proper divisors (191907739).

1343354117 is an equidigital number, since it uses as much as digits as its factorization.

1343354117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191907738.

The product of its digits is 15120, while the sum is 32.

The square root of 1343354117 is about 36651.7955494680. The cubic root of 1343354117 is about 1103.3928622441.

Adding to 1343354117 its reverse (7114533431), we get a palindrome (8457887548).

The spelling of 1343354117 in words is "one billion, three hundred forty-three million, three hundred fifty-four thousand, one hundred seventeen".

Divisors: 1 7 191907731 1343354117