1343368633431 has 108 divisors (see below), whose sum is σ = 2065155796536. Its totient is φ = 775603952640.

The previous prime is 1343368633391. The next prime is 1343368633487.

1343368633431 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1343368633431 - 2¹⁸ = 1343368371287 is a prime.

It is a super-4 number, since 4×1343368633431⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343368633031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 9805610395 + ... + 9805610531.

Almost surely, 2^{1343368633431} is an apocalyptic number.

1343368633431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1343368633431 is a deficient number, since it is larger than the sum of its proper divisors (721787163105).

1343368633431 is an equidigital number, since it uses as much as digits as its factorization.

1343368633431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 482 (or 261 counting only the distinct ones).

The product of its digits is 3359232, while the sum is 48.

The spelling of 1343368633431 in words is "one trillion, three hundred forty-three billion, three hundred sixty-eight million, six hundred thirty-three thousand, four hundred thirty-one".