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1343383271449 is a prime number
BaseRepresentation
bin10011100011000111111…
…000011111100000011001
311202102111200121222122121
4103203013320133200121
5134002222104141244
62505050341421241
7166025201254342
oct23430770374031
94672450558577
101343383271449
114787a892013a
1219843440a821
13998b009646b
144903d20b0c9
1524e2795cc84
hex138c7e1f819

1343383271449 has 2 divisors, whose sum is σ = 1343383271450. Its totient is φ = 1343383271448.

The previous prime is 1343383271401. The next prime is 1343383271467. The reversal of 1343383271449 is 9441723833431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1227371505424 + 116011766025 = 1107868^2 + 340605^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343383271449 - 211 = 1343383269401 is a prime.

It is a super-2 number, since 2×13433832714492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1343383271396 and 1343383271405.

It is not a weakly prime, because it can be changed into another prime (1343383271249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671691635724 + 671691635725.

It is an arithmetic number, because the mean of its divisors is an integer number (671691635725).

Almost surely, 21343383271449 is an apocalyptic number.

It is an amenable number.

1343383271449 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343383271449 is an equidigital number, since it uses as much as digits as its factorization.

1343383271449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5225472, while the sum is 52.

The spelling of 1343383271449 in words is "one trillion, three hundred forty-three billion, three hundred eighty-three million, two hundred seventy-one thousand, four hundred forty-nine".