1343410112025 has 84 divisors (see below), whose sum is σ = 2498839399980. Its totient is φ = 716129942400.

The previous prime is 1343410112021. The next prime is 1343410112039. The reversal of 1343410112025 is 5202110143431.

1343410112025 is a `hidden beast` number, since 1 + 3 + 43 + 410 + 1 + 1 + 202 + 5 = 666.

It can be written as a sum of positive squares in 6 ways, for example, as 2939374656 + 1340470737369 = 54216^2 + 1157787^2 .

It is not a de Polignac number, because 1343410112025 - 2² = 1343410112021 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a self number, because there is not a number n which added to its sum of digits gives 1343410112025.

It is not an unprimeable number, because it can be changed into a prime (1343410112021) by changing a digit.

It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 39002511 + ... + 39036939.

It is an arithmetic number, because the mean of its divisors is an integer number (29748088095).

Almost surely, 2^{1343410112025} is an apocalyptic number.

1343410112025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1343410112025 is a deficient number, since it is larger than the sum of its proper divisors (1155429287955).

1343410112025 is an equidigital number, since it uses as much as digits as its factorization.

1343410112025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36598 (or 36578 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1343410112025 its reverse (5202110143431), we get a palindrome (6545520255456).

The spelling of 1343410112025 in words is "one trillion, three hundred forty-three billion, four hundred ten million, one hundred twelve thousand, twenty-five".