Base | Representation |
---|---|
bin | 10011100011001001011… |
… | …110111000011000010101 |
3 | 11202102120120010121222212 |
4 | 103203021132320120111 |
5 | 134002300442041041 |
6 | 2505053141003205 |
7 | 166025645353625 |
oct | 23431136703025 |
9 | 4672516117885 |
10 | 1343410112021 |
11 | 478811a9292a |
12 | 1984413b3505 |
13 | 998b5803363 |
14 | 490429d6885 |
15 | 24e29eb08eb |
hex | 138c97b8615 |
1343410112021 has 2 divisors, whose sum is σ = 1343410112022. Its totient is φ = 1343410112020.
The previous prime is 1343410111999. The next prime is 1343410112039. The reversal of 1343410112021 is 1202110143431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 925609471396 + 417800640625 = 962086^2 + 646375^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343410112021 - 26 = 1343410111957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343410112071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671705056010 + 671705056011.
It is an arithmetic number, because the mean of its divisors is an integer number (671705056011).
Almost surely, 21343410112021 is an apocalyptic number.
It is an amenable number.
1343410112021 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343410112021 is an equidigital number, since it uses as much as digits as its factorization.
1343410112021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1343410112021 its reverse (1202110143431), we get a palindrome (2545520255452).
The spelling of 1343410112021 in words is "one trillion, three hundred forty-three billion, four hundred ten million, one hundred twelve thousand, twenty-one".
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