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134355223169 is a prime number
BaseRepresentation
bin111110100100000110…
…0100000001010000001
3110211210110001111122122
41331020030200022001
54200124414120134
6141415534414025
712464306360666
oct1751014401201
9424713044578
10134355223169
1151a86025822
1222057361315
13c89228a96b
146707a89a6d
1537653a502e
hex1f48320281

134355223169 has 2 divisors, whose sum is σ = 134355223170. Its totient is φ = 134355223168.

The previous prime is 134355223073. The next prime is 134355223217. The reversal of 134355223169 is 961322553431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120131560000 + 14223663169 = 346600^2 + 119263^2 .

It is an emirp because it is prime and its reverse (961322553431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134355223169 - 232 = 130060255873 is a prime.

It is a super-2 number, since 2×1343552231692 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134355223369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67177611584 + 67177611585.

It is an arithmetic number, because the mean of its divisors is an integer number (67177611585).

Almost surely, 2134355223169 is an apocalyptic number.

It is an amenable number.

134355223169 is a deficient number, since it is larger than the sum of its proper divisors (1).

134355223169 is an equidigital number, since it uses as much as digits as its factorization.

134355223169 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 583200, while the sum is 44.

The spelling of 134355223169 in words is "one hundred thirty-four billion, three hundred fifty-five million, two hundred twenty-three thousand, one hundred sixty-nine".