Base | Representation |
---|---|
bin | 111110100100010011… |
… | …1010100010000101011 |
3 | 110211210221021121211222 |
4 | 1331020213110100223 |
5 | 4200133214033311 |
6 | 141420345212255 |
7 | 12464423205116 |
oct | 1751047242053 |
9 | 424727247758 |
10 | 134362252331 |
11 | 51a89a9694a |
12 | 2205979108b |
13 | c89387c228 |
14 | 670899957d |
15 | 3765ce2adb |
hex | 1f489d442b |
134362252331 has 2 divisors, whose sum is σ = 134362252332. Its totient is φ = 134362252330.
The previous prime is 134362252313. The next prime is 134362252373. The reversal of 134362252331 is 133252263431.
Together with previous prime (134362252313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134362252331 is a prime.
It is a super-2 number, since 2×1343622523312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 134362252291 and 134362252300.
It is not a weakly prime, because it can be changed into another prime (134362252631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67181126165 + 67181126166.
It is an arithmetic number, because the mean of its divisors is an integer number (67181126166).
Almost surely, 2134362252331 is an apocalyptic number.
134362252331 is a deficient number, since it is larger than the sum of its proper divisors (1).
134362252331 is an equidigital number, since it uses as much as digits as its factorization.
134362252331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 35.
The spelling of 134362252331 in words is "one hundred thirty-four billion, three hundred sixty-two million, two hundred fifty-two thousand, three hundred thirty-one".
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