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134363513314211 is a prime number
BaseRepresentation
bin11110100011001111110001…
…011110110101101110100011
3122121202000201021010200020212
4132203033301132311232203
5120102402433402023321
61153433425035524335
740205305054666436
oct3643176136655643
9577660637120225
10134363513314211
11398a3278464115
12130a06708b96ab
1359c856a78823c
14252732b95981d
151080183b0255b
hex7a33f17b5ba3

134363513314211 has 2 divisors, whose sum is σ = 134363513314212. Its totient is φ = 134363513314210.

The previous prime is 134363513314139. The next prime is 134363513314229. The reversal of 134363513314211 is 112413315363431.

It is a strong prime.

It is an emirp because it is prime and its reverse (112413315363431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134363513314211 - 238 = 134088635407267 is a prime.

It is not a weakly prime, because it can be changed into another prime (134363513314231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67181756657105 + 67181756657106.

It is an arithmetic number, because the mean of its divisors is an integer number (67181756657106).

Almost surely, 2134363513314211 is an apocalyptic number.

134363513314211 is a deficient number, since it is larger than the sum of its proper divisors (1).

134363513314211 is an equidigital number, since it uses as much as digits as its factorization.

134363513314211 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 233280, while the sum is 41.

Adding to 134363513314211 its reverse (112413315363431), we get a palindrome (246776828677642).

The spelling of 134363513314211 in words is "one hundred thirty-four trillion, three hundred sixty-three billion, five hundred thirteen million, three hundred fourteen thousand, two hundred eleven".