Base | Representation |
---|---|
bin | 10011100011010111110… |
… | …111100100000010010001 |
3 | 11202110012101021112201121 |
4 | 103203113313210002101 |
5 | 134003244233311223 |
6 | 2505133122002241 |
7 | 166034635664665 |
oct | 23432767440221 |
9 | 4673171245647 |
10 | 1343651463313 |
11 | 478926249705 |
12 | 1984aa1a6381 |
13 | 99923808283 |
14 | 49066aa08a5 |
15 | 24e4128715d |
hex | 138d7de4091 |
1343651463313 has 2 divisors, whose sum is σ = 1343651463314. Its totient is φ = 1343651463312.
The previous prime is 1343651463263. The next prime is 1343651463337. The reversal of 1343651463313 is 3133641563431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1234981022209 + 108670441104 = 1111297^2 + 329652^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343651463313 - 29 = 1343651462801 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1343651463313.
It is not a weakly prime, because it can be changed into another prime (1343651263313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671825731656 + 671825731657.
It is an arithmetic number, because the mean of its divisors is an integer number (671825731657).
Almost surely, 21343651463313 is an apocalyptic number.
It is an amenable number.
1343651463313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343651463313 is an equidigital number, since it uses as much as digits as its factorization.
1343651463313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 699840, while the sum is 43.
The spelling of 1343651463313 in words is "one trillion, three hundred forty-three billion, six hundred fifty-one million, four hundred sixty-three thousand, three hundred thirteen".
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