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134365256063103 = 3133445262975977
BaseRepresentation
bin11110100011010001011001…
…010110111001100001111111
3122121202012012201102111022010
4132203101121112321201333
5120102420021023004403
61153434314013022303
740205366206056132
oct3643213126714177
9577665181374263
10134365256063103
11398a3a9217515a
12130a0a78484993
1359c87878515c0
1425274551ac219
151080236aec603
hex7a34595b987f

134365256063103 has 8 divisors (see below), whose sum is σ = 192934726654768. Its totient is φ = 82686311423424.

The previous prime is 134365256063029. The next prime is 134365256063117. The reversal of 134365256063103 is 301360652563431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 134365256063103 - 28 = 134365256062847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134365256063123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1722631487950 + ... + 1722631488027.

It is an arithmetic number, because the mean of its divisors is an integer number (24116840831846).

Almost surely, 2134365256063103 is an apocalyptic number.

134365256063103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

134365256063103 is a deficient number, since it is larger than the sum of its proper divisors (58569470591665).

134365256063103 is a wasteful number, since it uses less digits than its factorization.

134365256063103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3445262975993.

The product of its (nonzero) digits is 3499200, while the sum is 48.

The spelling of 134365256063103 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, two hundred fifty-six million, sixty-three thousand, one hundred three".

Divisors: 1 3 13 39 3445262975977 10335788927931 44788418687701 134365256063103