Base | Representation |
---|---|
bin | 11110100011010001011001… |
… | …010110111001100001111111 |
3 | 122121202012012201102111022010 |
4 | 132203101121112321201333 |
5 | 120102420021023004403 |
6 | 1153434314013022303 |
7 | 40205366206056132 |
oct | 3643213126714177 |
9 | 577665181374263 |
10 | 134365256063103 |
11 | 398a3a9217515a |
12 | 130a0a78484993 |
13 | 59c87878515c0 |
14 | 25274551ac219 |
15 | 1080236aec603 |
hex | 7a34595b987f |
134365256063103 has 8 divisors (see below), whose sum is σ = 192934726654768. Its totient is φ = 82686311423424.
The previous prime is 134365256063029. The next prime is 134365256063117. The reversal of 134365256063103 is 301360652563431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 134365256063103 - 28 = 134365256062847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134365256063123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1722631487950 + ... + 1722631488027.
It is an arithmetic number, because the mean of its divisors is an integer number (24116840831846).
Almost surely, 2134365256063103 is an apocalyptic number.
134365256063103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
134365256063103 is a deficient number, since it is larger than the sum of its proper divisors (58569470591665).
134365256063103 is a wasteful number, since it uses less digits than its factorization.
134365256063103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3445262975993.
The product of its (nonzero) digits is 3499200, while the sum is 48.
The spelling of 134365256063103 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, two hundred fifty-six million, sixty-three thousand, one hundred three".
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