Base | Representation |
---|---|
bin | 11110100011010001011001… |
… | …010110111001100010000000 |
3 | 122121202012012201102111022011 |
4 | 132203101121112321202000 |
5 | 120102420021023004404 |
6 | 1153434314013022304 |
7 | 40205366206056133 |
oct | 3643213126714200 |
9 | 577665181374264 |
10 | 134365256063104 |
11 | 398a3a92175160 |
12 | 130a0a78484994 |
13 | 59c87878515c1 |
14 | 25274551ac21a |
15 | 1080236aec604 |
hex | 7a34595b9880 |
134365256063104 has 64 divisors (see below), whose sum is σ = 292290112255680. Its totient is φ = 61017660288000.
The previous prime is 134365256063029. The next prime is 134365256063117. The reversal of 134365256063104 is 401360652563431.
It is a tau number, because it is divible by the number of its divisors (64).
It is a super-2 number, since 2×1343652560631042 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43390347 + ... + 46383754.
It is an arithmetic number, because the mean of its divisors is an integer number (4567033003995).
Almost surely, 2134365256063104 is an apocalyptic number.
It is an amenable number.
134365256063104 is an abundant number, since it is smaller than the sum of its proper divisors (157924856192576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134365256063104 is a wasteful number, since it uses less digits than its factorization.
134365256063104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89775189 (or 89775177 counting only the distinct ones).
The product of its (nonzero) digits is 4665600, while the sum is 49.
The spelling of 134365256063104 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, two hundred fifty-six million, sixty-three thousand, one hundred four".
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