Base | Representation |
---|---|
bin | 11110100011010001100100… |
… | …101101011101010111001011 |
3 | 122121202012200222211000211201 |
4 | 132203101210231131113023 |
5 | 120102420413302321121 |
6 | 1153434344535205031 |
7 | 40205404011013552 |
oct | 3643214455352713 |
9 | 577665628730751 |
10 | 134365446526411 |
11 | 398a407a734051 |
12 | 130a0b10216777 |
13 | 59c87b8149b99 |
14 | 25274725cad99 |
15 | 10802486c0e91 |
hex | 7a3464b5d5cb |
134365446526411 has 2 divisors, whose sum is σ = 134365446526412. Its totient is φ = 134365446526410.
The previous prime is 134365446526403. The next prime is 134365446526517. The reversal of 134365446526411 is 114625644563431.
It is a weak prime.
It is an emirp because it is prime and its reverse (114625644563431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134365446526411 - 23 = 134365446526403 is a prime.
It is not a weakly prime, because it can be changed into another prime (134365446506411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67182723263205 + 67182723263206.
It is an arithmetic number, because the mean of its divisors is an integer number (67182723263206).
Almost surely, 2134365446526411 is an apocalyptic number.
134365446526411 is a deficient number, since it is larger than the sum of its proper divisors (1).
134365446526411 is an equidigital number, since it uses as much as digits as its factorization.
134365446526411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24883200, while the sum is 55.
The spelling of 134365446526411 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, four hundred forty-six million, five hundred twenty-six thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •