Base | Representation |
---|---|
bin | 11110100011010010001100… |
… | …011001110001000000101100 |
3 | 122121202021102101212120220120 |
4 | 132203102030121301000230 |
5 | 120102423244241441102 |
6 | 1153434535004244540 |
7 | 40205426345211513 |
oct | 3643221431610054 |
9 | 577667371776816 |
10 | 134366112452652 |
11 | 398a4391620313 |
12 | 130a1077240750 |
13 | 59c88930b8c92 |
14 | 25274d6c1567a |
15 | 1080286db26bc |
hex | 7a348c67102c |
134366112452652 has 24 divisors (see below), whose sum is σ = 313619862855600. Its totient is φ = 44774570750976.
The previous prime is 134366112452641. The next prime is 134366112452659. The reversal of 134366112452652 is 256254211663431.
It is a junction number, because it is equal to n+sod(n) for n = 134366112452595 and 134366112452604.
It is not an unprimeable number, because it can be changed into a prime (134366112452659) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1766635377 + ... + 1766711432.
It is an arithmetic number, because the mean of its divisors is an integer number (13067494285650).
Almost surely, 2134366112452652 is an apocalyptic number.
134366112452652 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134366112452652 is an abundant number, since it is smaller than the sum of its proper divisors (179253750402948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134366112452652 is a wasteful number, since it uses less digits than its factorization.
134366112452652 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3533349985 (or 3533349983 counting only the distinct ones).
The product of its digits is 6220800, while the sum is 51.
The spelling of 134366112452652 in words is "one hundred thirty-four trillion, three hundred sixty-six billion, one hundred twelve million, four hundred fifty-two thousand, six hundred fifty-two".
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