Base | Representation |
---|---|
bin | 11110100011010110110011… |
… | …101011101100111101000011 |
3 | 122121202202012122122212212001 |
4 | 132203112303223230331003 |
5 | 120103013421001331342 |
6 | 1153441114333244431 |
7 | 40205663201311102 |
oct | 3643266353547503 |
9 | 577682178585761 |
10 | 134371066433347 |
11 | 398a64a3a56337 |
12 | 130a201a333717 |
13 | 59c91a25542c3 |
14 | 2527846b38039 |
15 | 1080476c788b7 |
hex | 7a35b3aecf43 |
134371066433347 has 2 divisors, whose sum is σ = 134371066433348. Its totient is φ = 134371066433346.
The previous prime is 134371066433273. The next prime is 134371066433393. The reversal of 134371066433347 is 743334660173431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134371066433347 - 239 = 133821310619459 is a prime.
It is not a weakly prime, because it can be changed into another prime (134371066433147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67185533216673 + 67185533216674.
It is an arithmetic number, because the mean of its divisors is an integer number (67185533216674).
Almost surely, 2134371066433347 is an apocalyptic number.
134371066433347 is a deficient number, since it is larger than the sum of its proper divisors (1).
134371066433347 is an equidigital number, since it uses as much as digits as its factorization.
134371066433347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27433728, while the sum is 55.
The spelling of 134371066433347 in words is "one hundred thirty-four trillion, three hundred seventy-one billion, sixty-six million, four hundred thirty-three thousand, three hundred forty-seven".
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