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134371066434373 = 848671158331163
BaseRepresentation
bin11110100011010110110011…
…101011101101001101000101
3122121202202012122122221021001
4132203112303223231031011
5120103013421001344443
61153441114333253301
740205663201314066
oct3643266353551505
9577682178587231
10134371066434373
11398a64a3a5708a
12130a201a334231
1359c91a2554902
142527846b3856d
151080476c78d4d
hex7a35b3aed345

134371066434373 has 4 divisors (see below), whose sum is σ = 134371225614208. Its totient is φ = 134370907254540.

The previous prime is 134371066434317. The next prime is 134371066434379. The reversal of 134371066434373 is 373434660173431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134371066434373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134371066434379) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78316911 + ... + 80014252.

It is an arithmetic number, because the mean of its divisors is an integer number (33592806403552).

Almost surely, 2134371066434373 is an apocalyptic number.

It is an amenable number.

134371066434373 is a deficient number, since it is larger than the sum of its proper divisors (159179835).

134371066434373 is an equidigital number, since it uses as much as digits as its factorization.

134371066434373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159179834.

The product of its (nonzero) digits is 27433728, while the sum is 55.

The spelling of 134371066434373 in words is "one hundred thirty-four trillion, three hundred seventy-one billion, sixty-six million, four hundred thirty-four thousand, three hundred seventy-three".

Divisors: 1 848671 158331163 134371066434373