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134371066434317 is a prime number
BaseRepresentation
bin11110100011010110110011…
…101011101101001100001101
3122121202202012122122221011222
4132203112303223231030031
5120103013421001344232
61153441114333253125
740205663201313656
oct3643266353551415
9577682178587158
10134371066434317
11398a64a3a57039
12130a201a3341a5
1359c91a255488b
142527846b3852d
151080476c78d12
hex7a35b3aed30d

134371066434317 has 2 divisors, whose sum is σ = 134371066434318. Its totient is φ = 134371066434316.

The previous prime is 134371066434251. The next prime is 134371066434379. The reversal of 134371066434317 is 713434660173431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110289924613801 + 24081141820516 = 10501901^2 + 4907254^2 .

It is a cyclic number.

It is not a de Polignac number, because 134371066434317 - 230 = 134369992692493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134371066404317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67185533217158 + 67185533217159.

It is an arithmetic number, because the mean of its divisors is an integer number (67185533217159).

Almost surely, 2134371066434317 is an apocalyptic number.

It is an amenable number.

134371066434317 is a deficient number, since it is larger than the sum of its proper divisors (1).

134371066434317 is an equidigital number, since it uses as much as digits as its factorization.

134371066434317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9144576, while the sum is 53.

The spelling of 134371066434317 in words is "one hundred thirty-four trillion, three hundred seventy-one billion, sixty-six million, four hundred thirty-four thousand, three hundred seventeen".