Base | Representation |
---|---|
bin | 11110100011011011110101… |
… | …010010101010110100001110 |
3 | 122121210021010200121220102001 |
4 | 132203123311102222310032 |
5 | 120103110443301301132 |
6 | 1153443410002022514 |
7 | 40206244000104265 |
oct | 3643336522526416 |
9 | 577707120556361 |
10 | 134376462134542 |
11 | 398a8812762521 |
12 | 130a3085347a3a |
13 | 59c985237a8c4 |
14 | 2527bd95a15dc |
15 | 10806907e4ce7 |
hex | 7a36f54aad0e |
134376462134542 has 4 divisors (see below), whose sum is σ = 201564693201816. Its totient is φ = 67188231067270.
The previous prime is 134376462134521. The next prime is 134376462134587. The reversal of 134376462134542 is 245431264673431.
134376462134542 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33594115533634 + ... + 33594115533637.
It is an arithmetic number, because the mean of its divisors is an integer number (50391173300454).
Almost surely, 2134376462134542 is an apocalyptic number.
134376462134542 is a deficient number, since it is larger than the sum of its proper divisors (67188231067274).
134376462134542 is an equidigital number, since it uses as much as digits as its factorization.
134376462134542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67188231067273.
The product of its digits is 34836480, while the sum is 55.
The spelling of 134376462134542 in words is "one hundred thirty-four trillion, three hundred seventy-six billion, four hundred sixty-two million, one hundred thirty-four thousand, five hundred forty-two".
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