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13438113491 = 111221646681
BaseRepresentation
bin11001000001111100…
…10101011011010011
31021200112011220012002
430200332111123103
5210010124112431
610101241224215
7654003036305
oct144076253323
937615156162
1013438113491
115776512620
12273049206b
13136209925a
14916a11975
15539b433cb
hex320f956d3

13438113491 has 4 divisors (see below), whose sum is σ = 14659760184. Its totient is φ = 12216466800.

The previous prime is 13438113473. The next prime is 13438113497. The reversal of 13438113491 is 19431183431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13438113491 - 214 = 13438097107 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13438113497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610823330 + ... + 610823351.

It is an arithmetic number, because the mean of its divisors is an integer number (3664940046).

Almost surely, 213438113491 is an apocalyptic number.

13438113491 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13438113491 is a deficient number, since it is larger than the sum of its proper divisors (1221646693).

13438113491 is a wasteful number, since it uses less digits than its factorization.

13438113491 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1221646692.

The product of its digits is 31104, while the sum is 38.

The spelling of 13438113491 in words is "thirteen billion, four hundred thirty-eight million, one hundred thirteen thousand, four hundred ninety-one".

Divisors: 1 11 1221646681 13438113491