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134385763234031 = 730199918403969
BaseRepresentation
bin11110100011100100011111…
…101011100011000011101111
3122121211011010220021201021022
4132203210133223203003233
5120103234020341442111
61153451544540524355
740210023330124361
oct3643443753430357
9577734126251238
10134385763234031
1139901755a09201
12130a4a402506bb
1359ca6a532227a
14252843c994d31
151080a3714b2db
hex7a391fae30ef

134385763234031 has 4 divisors (see below), whose sum is σ = 134385788940000. Its totient is φ = 134385737528064.

The previous prime is 134385763233983. The next prime is 134385763234061. The reversal of 134385763234031 is 130432367583431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134385763234031 is a prime.

It is a super-2 number, since 2×1343857632340312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134385763234061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1899986 + ... + 16503983.

It is an arithmetic number, because the mean of its divisors is an integer number (33596447235000).

Almost surely, 2134385763234031 is an apocalyptic number.

134385763234031 is a deficient number, since it is larger than the sum of its proper divisors (25705969).

134385763234031 is an equidigital number, since it uses as much as digits as its factorization.

134385763234031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25705968.

The product of its (nonzero) digits is 13063680, while the sum is 53.

The spelling of 134385763234031 in words is "one hundred thirty-four trillion, three hundred eighty-five billion, seven hundred sixty-three million, two hundred thirty-four thousand, thirty-one".

Divisors: 1 7301999 18403969 134385763234031