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1343990922913 is a prime number
BaseRepresentation
bin10011100011101100000…
…110011111111010100001
311202111002001000212202101
4103203230012133322201
5134004443134013123
62505230525450401
7166046230232062
oct23435406377241
94674061025671
101343990922913
11478a8a924731
12198583a10a01
1399978c40942
1449099bc6569
1524e60e8caad
hex138ec19fea1

1343990922913 has 2 divisors, whose sum is σ = 1343990922914. Its totient is φ = 1343990922912.

The previous prime is 1343990922899. The next prime is 1343990922983. The reversal of 1343990922913 is 3192290993431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 867686661009 + 476304261904 = 931497^2 + 690148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1343990922913 is a prime.

It is not a weakly prime, because it can be changed into another prime (1343990922983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671995461456 + 671995461457.

It is an arithmetic number, because the mean of its divisors is an integer number (671995461457).

Almost surely, 21343990922913 is an apocalyptic number.

It is an amenable number.

1343990922913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343990922913 is an equidigital number, since it uses as much as digits as its factorization.

1343990922913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2834352, while the sum is 55.

The spelling of 1343990922913 in words is "one trillion, three hundred forty-three billion, nine hundred ninety million, nine hundred twenty-two thousand, nine hundred thirteen".