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1343996083 is a prime number
BaseRepresentation
bin101000000011011…
…1100000010110011
310110122222002000201
41100012330002303
510223030333313
6341210300031
745206530633
oct12006740263
93418862021
101343996083
1162a718171
12316127617
131855a0671
14ca6d46c3
157ced10dd
hex501bc0b3

1343996083 has 2 divisors, whose sum is σ = 1343996084. Its totient is φ = 1343996082.

The previous prime is 1343996057. The next prime is 1343996107. The reversal of 1343996083 is 3806993431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1343996083 - 213 = 1343987891 is a prime.

It is a super-2 number, since 2×13439960832 = 3612650942238685778, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1343996023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671998041 + 671998042.

It is an arithmetic number, because the mean of its divisors is an integer number (671998042).

Almost surely, 21343996083 is an apocalyptic number.

1343996083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343996083 is an equidigital number, since it uses as much as digits as its factorization.

1343996083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 46.

The square root of 1343996083 is about 36660.5521371405. The cubic root of 1343996083 is about 1103.5685984576.

The spelling of 1343996083 in words is "one billion, three hundred forty-three million, nine hundred ninety-six thousand, eighty-three".