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13440000000000 = 21635107
BaseRepresentation
bin1100001110010011111001…
…1011010000000000000000
31202120211222201010102202210
43003210332123100000000
53230200110000000000
644330130055342120
72555002505033250
oct303447633200000
952524881112683
1013440000000000
114311965690132
121610918981940
13766504378cc2
143466dc795960
15184912a67350
hexc393e6d0000

13440000000000 has 748 divisors, whose sum is σ = 51199608326432. Its totient is φ = 3072000000000.

The previous prime is 13439999999999. The next prime is 13440000000013. The reversal of 13440000000000 is 4431.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 43 ways as a sum of consecutive naturals, for example, 1919999999997 + ... + 1920000000003.

Almost surely, 213440000000000 is an apocalyptic number.

13440000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13440000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25599804163216).

13440000000000 is an abundant number, since it is smaller than the sum of its proper divisors (37759608326432).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13440000000000 is an frugal number, since it uses more digits than its factorization.

13440000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92 (or 17 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 13440000000000 its reverse (4431), we get a palindrome (13440000004431).

The spelling of 13440000000000 in words is "thirteen trillion, four hundred forty billion", and thus it is an aban number.