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1344000523 is a prime number
BaseRepresentation
bin101000000011011…
…1101001000001011
310110122222022010011
41100012331020023
510223031004043
6341210332351
745206546605
oct12006751013
93418868104
101344000523
1162a720538
1231612a0b7
131855a26a8
14ca6d6175
157ced259d
hex501bd20b

1344000523 has 2 divisors, whose sum is σ = 1344000524. Its totient is φ = 1344000522.

The previous prime is 1344000509. The next prime is 1344000527. The reversal of 1344000523 is 3250004431.

It is a strong prime.

It is an emirp because it is prime and its reverse (3250004431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344000523 - 29 = 1344000011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1344000494 and 1344000503.

It is not a weakly prime, because it can be changed into another prime (1344000527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672000261 + 672000262.

It is an arithmetic number, because the mean of its divisors is an integer number (672000262).

Almost surely, 21344000523 is an apocalyptic number.

1344000523 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344000523 is an equidigital number, since it uses as much as digits as its factorization.

1344000523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 1344000523 is about 36660.6126926433. The cubic root of 1344000523 is about 1103.5698136990.

Adding to 1344000523 its reverse (3250004431), we get a palindrome (4594004954).

The spelling of 1344000523 in words is "one billion, three hundred forty-four million, five hundred twenty-three", and thus it is an aban number.