Base | Representation |
---|---|
bin | 11001000010001011… |
… | …01111100001100001 |
3 | 1021200122211112222101 |
4 | 30201011233201201 |
5 | 210011123233033 |
6 | 10101351010401 |
7 | 654025404652 |
oct | 144105574141 |
9 | 37618745871 |
10 | 13440055393 |
11 | 57776195a6 |
12 | 2731069a01 |
13 | 13625c90cb |
14 | 916d99529 |
15 | 539dc897d |
hex | 32116f861 |
13440055393 has 2 divisors, whose sum is σ = 13440055394. Its totient is φ = 13440055392.
The previous prime is 13440055351. The next prime is 13440055427. The reversal of 13440055393 is 39355004431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13412419344 + 27636049 = 115812^2 + 5257^2 .
It is an emirp because it is prime and its reverse (39355004431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13440055393 - 217 = 13439924321 is a prime.
It is not a weakly prime, because it can be changed into another prime (13440055693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720027696 + 6720027697.
It is an arithmetic number, because the mean of its divisors is an integer number (6720027697).
Almost surely, 213440055393 is an apocalyptic number.
It is an amenable number.
13440055393 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440055393 is an equidigital number, since it uses as much as digits as its factorization.
13440055393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 13440055393 in words is "thirteen billion, four hundred forty million, fifty-five thousand, three hundred ninety-three".
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