Base | Representation |
---|---|
bin | 10011100011101101010… |
… | …000000011001110001001 |
3 | 11202111010101022110111020 |
4 | 103203231100003032021 |
5 | 134010013103012131 |
6 | 2505232455023053 |
7 | 166046553145221 |
oct | 23435520031611 |
9 | 4674111273436 |
10 | 1344010204041 |
11 | 478a9a7a394a |
12 | 19858a36aa89 |
13 | 9997cc31aab |
14 | 4909c5a5081 |
15 | 24e629ea996 |
hex | 138ed403389 |
1344010204041 has 4 divisors (see below), whose sum is σ = 1792013605392. Its totient is φ = 896006802692.
The previous prime is 1344010204013. The next prime is 1344010204111. The reversal of 1344010204041 is 1404020104431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1344010204041 - 214 = 1344010187657 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1344010208041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224001700671 + ... + 224001700676.
It is an arithmetic number, because the mean of its divisors is an integer number (448003401348).
Almost surely, 21344010204041 is an apocalyptic number.
It is an amenable number.
1344010204041 is a deficient number, since it is larger than the sum of its proper divisors (448003401351).
1344010204041 is an equidigital number, since it uses as much as digits as its factorization.
1344010204041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 448003401350.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1344010204041 its reverse (1404020104431), we get a palindrome (2748030308472).
The spelling of 1344010204041 in words is "one trillion, three hundred forty-four billion, ten million, two hundred four thousand, forty-one".
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