1344010204013 has 2 divisors, whose sum is σ = 1344010204014. Its totient is φ = 1344010204012.

The previous prime is 1344010203941. The next prime is 1344010204111. The reversal of 1344010204013 is 3104020104431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1337913249124 + 6096954889 = 1156682^2 + 78083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344010204013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1344010204013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344010204213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005102006 + 672005102007.

It is an arithmetic number, because the mean of its divisors is an integer number (672005102007).

Almost surely, 2^{1344010204013} is an apocalyptic number.

It is an amenable number.

1344010204013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344010204013 is an equidigital number, since it uses as much as digits as its factorization.

1344010204013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1344010204013 its reverse (3104020104431), we get a palindrome (4448030308444).

The spelling of 1344010204013 in words is "one trillion, three hundred forty-four billion, ten million, two hundred four thousand, thirteen".