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134401104350102 = 267200552175051
BaseRepresentation
bin11110100011110010110010…
…000101010000101110010110
3122121212121202001022011020102
4132203302302011100232112
5120104011430203200402
61153503003122134102
740211105441350322
oct3643626205205626
9577777661264212
10134401104350102
1139908208637827
12130a7a01ab1332
1359cbc7b733945
142529096212982
151081133d92102
hex7a3cb2150b96

134401104350102 has 4 divisors (see below), whose sum is σ = 201601656525156. Its totient is φ = 67200552175050.

The previous prime is 134401104350099. The next prime is 134401104350143. The reversal of 134401104350102 is 201053401104431.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33600276087524 + ... + 33600276087527.

It is an arithmetic number, because the mean of its divisors is an integer number (50400414131289).

Almost surely, 2134401104350102 is an apocalyptic number.

134401104350102 is a deficient number, since it is larger than the sum of its proper divisors (67200552175054).

134401104350102 is an equidigital number, since it uses as much as digits as its factorization.

134401104350102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67200552175053.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 134401104350102 its reverse (201053401104431), we get a palindrome (335454505454533).

The spelling of 134401104350102 in words is "one hundred thirty-four trillion, four hundred one billion, one hundred four million, three hundred fifty thousand, one hundred two".

Divisors: 1 2 67200552175051 134401104350102