Base | Representation |
---|---|
bin | 11110100011110010110110… |
… | …010101001111010110111011 |
3 | 122121212121221000110110010021 |
4 | 132203302312111033112323 |
5 | 120104012101431211200 |
6 | 1153503014150231311 |
7 | 40211110265360056 |
oct | 3643626625172673 |
9 | 577777830413107 |
10 | 134401175647675 |
11 | 39908244904742 |
12 | 130a7a21955537 |
13 | 59cbc90437c61 |
14 | 25290a1891a9d |
15 | 108113a27741a |
hex | 7a3cb654f5bb |
134401175647675 has 12 divisors (see below), whose sum is σ = 168530013511560. Its totient is φ = 106312840061120.
The previous prime is 134401175647649. The next prime is 134401175647709. The reversal of 134401175647675 is 576746571104431.
It is a happy number.
It is not a de Polignac number, because 134401175647675 - 25 = 134401175647643 is a prime.
It is a super-3 number, since 3×1344011756476753 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30202509157 + ... + 30202513606.
It is an arithmetic number, because the mean of its divisors is an integer number (14044167792630).
Almost surely, 2134401175647675 is an apocalyptic number.
134401175647675 is a deficient number, since it is larger than the sum of its proper divisors (34128837863885).
134401175647675 is an equidigital number, since it uses as much as digits as its factorization.
134401175647675 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60405022862 (or 60405022857 counting only the distinct ones).
The product of its (nonzero) digits is 59270400, while the sum is 61.
The spelling of 134401175647675 in words is "one hundred thirty-four trillion, four hundred one billion, one hundred seventy-five million, six hundred forty-seven thousand, six hundred seventy-five".
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