1344012281 has 2 divisors, whose sum is σ = 1344012282. Its totient is φ = 1344012280.

The previous prime is 1344012211. The next prime is 1344012287. The reversal of 1344012281 is 1822104431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 733922281 + 610090000 = 27091^2 + 24700^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344012281 is a prime.

It is a super-2 number, since 2×1344012281² = 3612738022957645922, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1344012281.

It is not a weakly prime, because it can be changed into another prime (1344012287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672006140 + 672006141.

It is an arithmetic number, because the mean of its divisors is an integer number (672006141).

Almost surely, 2^1344012281 is an apocalyptic number.

It is an amenable number.

1344012281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344012281 is an equidigital number, since it uses as much as digits as its factorization.

1344012281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

The square root of 1344012281 is about 36660.7730551335. The cubic root of 1344012281 is about 1103.5730318862.

The spelling of 1344012281 in words is "one billion, three hundred forty-four million, twelve thousand, two hundred eighty-one".