Base | Representation |
---|---|
bin | 11110100011110010111101… |
… | …110001111101000111000011 |
3 | 122121212122020201121110220122 |
4 | 132203302331301331013003 |
5 | 120104012330424144434 |
6 | 1153503034412530455 |
7 | 40211113343522102 |
oct | 3643627561750703 |
9 | 577778221543818 |
10 | 134401300615619 |
11 | 399082a93a9a34 |
12 | 130a7a57780a2b |
13 | 59cbcb02b119b |
14 | 25290b4302039 |
15 | 108114620ec2e |
hex | 7a3cbdc7d1c3 |
134401300615619 has 2 divisors, whose sum is σ = 134401300615620. Its totient is φ = 134401300615618.
The previous prime is 134401300615573. The next prime is 134401300615651. The reversal of 134401300615619 is 916516003104431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134401300615619 is a prime.
It is a super-2 number, since 2×1344013006156192 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 134401300615619.
It is not a weakly prime, because it can be changed into another prime (134401300612619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200650307809 + 67200650307810.
It is an arithmetic number, because the mean of its divisors is an integer number (67200650307810).
Almost surely, 2134401300615619 is an apocalyptic number.
134401300615619 is a deficient number, since it is larger than the sum of its proper divisors (1).
134401300615619 is an equidigital number, since it uses as much as digits as its factorization.
134401300615619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 233280, while the sum is 44.
The spelling of 134401300615619 in words is "one hundred thirty-four trillion, four hundred one billion, three hundred million, six hundred fifteen thousand, six hundred nineteen".
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