13440132022 has 4 divisors (see below), whose sum is σ = 20160198036. Its totient is φ = 6720066010.

The previous prime is 13440132019. The next prime is 13440132023. The reversal of 13440132022 is 22023104431.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13440131984 and 13440132002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440132023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360033004 + ... + 3360033007.

It is an arithmetic number, because the mean of its divisors is an integer number (5040049509).

Almost surely, 2^13440132022 is an apocalyptic number.

13440132022 is a deficient number, since it is larger than the sum of its proper divisors (6720066014).

13440132022 is an equidigital number, since it uses as much as digits as its factorization.

13440132022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6720066013.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13440132022 its reverse (22023104431), we get a palindrome (35463236453).

The spelling of 13440132022 in words is "thirteen billion, four hundred forty million, one hundred thirty-two thousand, twenty-two".