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1344024217 is a prime number
BaseRepresentation
bin101000000011100…
…0010111010011001
310110200000111121201
41100013002322121
510223032233332
6341211034201
745210005644
oct12007027231
93420014551
101344024217
1162a737318
1231613b961
131855b0403
14ca700a5b
157ced95e7
hex501c2e99

1344024217 has 2 divisors, whose sum is σ = 1344024218. Its totient is φ = 1344024216.

The previous prime is 1344024193. The next prime is 1344024257. The reversal of 1344024217 is 7124204431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1280279961 + 63744256 = 35781^2 + 7984^2 .

It is an emirp because it is prime and its reverse (7124204431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344024217 - 215 = 1343991449 is a prime.

It is not a weakly prime, because it can be changed into another prime (1344024257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672012108 + 672012109.

It is an arithmetic number, because the mean of its divisors is an integer number (672012109).

Almost surely, 21344024217 is an apocalyptic number.

It is an amenable number.

1344024217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344024217 is an equidigital number, since it uses as much as digits as its factorization.

1344024217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 28.

The square root of 1344024217 is about 36660.9358445744. The cubic root of 1344024217 is about 1103.5762987732.

Adding to 1344024217 its reverse (7124204431), we get a palindrome (8468228648).

The spelling of 1344024217 in words is "one billion, three hundred forty-four million, twenty-four thousand, two hundred seventeen".