Base | Representation |
---|---|
bin | 111110100101100001… |
… | …0111010010010010011 |
3 | 110211220210000212120022 |
4 | 1331023002322102103 |
5 | 4200224134243103 |
6 | 141424403334055 |
7 | 12465426664562 |
oct | 1751302722223 |
9 | 424823025508 |
10 | 134403040403 |
11 | 520000155a5 |
12 | 2206b38132b |
13 | c89c160698 |
14 | 6710175bd9 |
15 | 376969d138 |
hex | 1f4b0ba493 |
134403040403 has 2 divisors, whose sum is σ = 134403040404. Its totient is φ = 134403040402.
The previous prime is 134403040363. The next prime is 134403040423. The reversal of 134403040403 is 304040304431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134403040403 is a prime.
It is not a weakly prime, because it can be changed into another prime (134403040423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67201520201 + 67201520202.
It is an arithmetic number, because the mean of its divisors is an integer number (67201520202).
Almost surely, 2134403040403 is an apocalyptic number.
134403040403 is a deficient number, since it is larger than the sum of its proper divisors (1).
134403040403 is an equidigital number, since it uses as much as digits as its factorization.
134403040403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 134403040403 its reverse (304040304431), we get a palindrome (438443344834).
The spelling of 134403040403 in words is "one hundred thirty-four billion, four hundred three million, forty thousand, four hundred three".
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